Convert a number to words
Here is a function that converts a given numeric value to words in dollars or other currency. You can use this for your check writing application where you need to put the dollar amount in words in your checks.
For example:
? InWords(1234567890123.45)
should return:
One Trillion Two Hundred Thirty Four Billion Five Hundred Sixty Seven Million Eight Hundred Ninety Thousand One Hundred Twenty Three And 45/100 Dollars Only
Here’s the code:
Public Function InWords(varAmount As Variant) As String
Dim strInWords As String
Dim decAmount As Variant
Dim intHundreds As Integer
Dim intDecimal As Integer
Dim strThou(5) As String
Dim ctr As Byte
' Value should be less than 10 Trillion
If varAmount > 9999999999999.99@ Then
InWords = "*** Value too large to convert ***"
Exit Function
Else
decAmount = CDec(varAmount)
End If
strThou(1) = ""
strThou(2) = " Thousand "
strThou(3) = " Million "
strThou(4) = " Billion "
strThou(5) = " Trillion "
intDecimal = CInt((decAmount - Int(decAmount)) * 100)
decAmount = Int(decAmount)
For ctr = 1 To 5
intHundreds = ((decAmount / 1000) - Int(decAmount / 1000)) * 1000
If intHundreds > 0 Then
strInWords = Hundreds(intHundreds) & strThou(ctr) & strInWords
End If
If decAmount >= 1 Then
decAmount = Int(decAmount / 1000)
Else
Exit For
End If
Next ctr
InWords = strInWords & " And " & intDecimal & "/100 Dollars Only"
End Function
Public Function Hundreds(intAmount As Integer) As String
Static varOnes As Variant
Static varTens As Variant
Dim strWords As String
Dim bOnes As Byte
Dim bTens As Byte
Dim bTeens As Byte
Dim bHundreds As Byte
If intAmount > 999 Then
Hundreds = "***Parameter should be less than 999***"
Exit Function
End If
If IsEmpty(varOnes) Then
varOnes = Array("", "One", "Two", "Three", "Four", "Five", _"Six", "Seven", "Eight", "Nine", "Ten", "Eleven", "Twelve", _
"Thirteen", "Fourteen", "Fifteen", "Sixteen", "Seventeen", _
"Eighteen", "Nineteen")
End If
If IsEmpty(varTens) Then
varTens = Array("", "Ten", "Twenty", "Thirty", "Forty", _"Fifty", "Sixty", "Seventy", "Eighty", "Ninety")
End If
bHundreds = Int(intAmount / 100)
If bHundreds > 0 Then
strWords = varOnes(bHundreds) & " Hundred "
End If
bTeens = ((intAmount / 100) - Int(intAmount / 100)) * 100
If bTeens < 20 Then
strWords = strWords & varOnes(bTeens)
Else
bTens = Int(intAmount / 10) - (Int(intAmount / 100) * 10)
If bTens > 0 Then
strWords = strWords & varTens(bTens) & " "
End If
bOnes = intAmount - (Int(intAmount / 10) * 10)
If bOnes > 0 Then
strWords = strWords & varOnes(bOnes)
End If
End If
Hundreds = strWords
End Function
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Allow User to Add Values in Combo Box
It is often good practice to provide users with a list of values that they can assign to a field when entering data into a Microsoft Access database form. With the use of pre-filled lists like a combo box, you can prevent the user from making incorrect data entry, and minimize the chance of spelling mistakes or incorrect choice of values. On some occasions, however, you may wish to allow the user to add new values to the underlying table. I do this for a field like City as part of a contact address where I would give the user the ability to define a new City that is not on the original list. This case would call for you to make use of the ComboBox’s NotInList event. To make it work, make sure that the following properties are set: Here’s the sample code for the NotInList event:
Private Sub cbxSYAddressCityID_NotInList( _
NewData As String, Response As Integer)
Dim strMsg As String
Dim strSQL As String
' Exit if the combo box was cleared ' Delete this line if the field is required If Len(NewData) = 0 Then Exit Sub
' Confirm that the user wants to add the new city strMsg = """" & NewData & """" & " is not in the list." _
& vbCr & vbCr & "Do you want to add it?" If MsgBox(strMsg, vbQuestion + vbYesNo) = vbNo Then
' If the user chose not to add the city, set the ' Response argument to suppress an error message ' and undo changes. Response = acDataErrContinue
' Display a customized message. cbxSYAddressCityID.SetFocus
Else ' If the user chose to add the new city, insert ' it the SYCity table strSQL = "INSERT INTO SYCity (SYCityName)" _ & " VALUES (" & """" & NewData & """" & ");"
' SetWarnings to False so the Dialog to confirm ' new record won't appear DoCmd.SetWarnings False DoCmd.RunSQL strSQL
' SetWarnings to True again DoCmd.SetWarnings True ' Set Response argument to indicate that new data ' is being added. Response = acDataErrAdded
End If
End Sub
Opening a Dialog Form When Printing a Report
Before printing a report, you normally would want to enter report parameters in a dialog box such as the following:
The dialog form will popup when you open the Payroll Register report shown below:
To do this, we just need to put a code in the Open event of the report to open the dialog form as follows:
Private Sub Report_Open(Cancel As Integer)
DoCmd.OpenForm "frmReportCriteria", acNormal, , , _
acFormEdit, acDialog, "rptPayrollRegisterPerPeriod"
If Not IsLoaded("frmReportCriteria") Then
Cancel = True
End If
End SubIn the Close event of the report, we’ll need to close the form:
Private Sub Report_Close() Forms![frmReportCriteria].Visible = True DoCmd.Close acForm, "frmReportCriteria" End Sub
In the Print button of the form, we can enter the following code:
Private Sub btnPrint_Click() On Error GoTo Err_btnPrint_Click Dim strDocName As String Dim strFilter As String ' OpenArgs contains the report name strDocName = Me.OpenArgs If fmeForEmployee = 1 Then ' All employees strFilter = "" Else ' Or individual employees strFilter = "[EmployeeID] = " & EmployeeID & " AND " End If strFilter = strFilter & "[PayPeriodID] Between " _ & FromPayPeriodID & " And " & ToPayPeriodID Reports.Item(strDocName).Filter = strFilter Reports.Item(strDocName).FilterOn = True Me.Visible = False Exit_btnPrint_Click: Exit Sub Err_btnPrint_Click: MsgBox Err.Description Resume Exit_btnPrint_Click End Sub
The code gets the report name from the OpenArgs passed by the report when it opens the dialog form. It then set the Filter property of the report to show only the records we selected in the form.
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Convert Numbers into String with Ordinal Suffix
The VBA code below allows you to represent a numeric value as its ordinal position in a set. The VBA function takes a numeric value and returns the number with the correct ordinal suffix as a string.
For example:
- strOrdinal(1)
- strOrdinal(42)
The strOrdinal function uses the Mod operator to get the last two digits of the number. For all values between 11 and 19, apply “th” as the suffix. Otherwise, it again uses Mod operator to get the last digit of the number and apply the following rules:
- Numbers that end in 1, use “st”
- Numbers that end in 2, use "nd"
- Numbers that end in 3, use "rd"
- Otherwise, use "th"
Here’s the code for the function that converts numbers into a string with ordinal suffix:
Public Function strOrdinal(lngVal As Long) As String
Dim intDigit As Integer
Dim intTeen As Integer
Dim strSuffix As String
' Check for the "teens" first
intTeen = lngVal Mod 100
If intTeen >= 11 And intTeen <= 19 Then
' if teens, use "th"
strSuffix = "th"
Else
' Get the last digit
intDigit = lngVal Mod 10
Select Case intDigit
Case 1
strSuffix = "st"
Case 2
strSuffix = "nd"
Case 3
strSuffix = "rd"
Case Else
strSuffix = "th"
End Select
End If
strOrdinal = lngVal & strSuffix
End Function
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